Optimal. Leaf size=206 \[ \frac {2 (d+e x)^8}{5 e \left (d^2-e^2 x^2\right )^{5/2}}-\frac {22 (d+e x)^6}{15 e \left (d^2-e^2 x^2\right )^{3/2}}+\frac {66 (d+e x)^4}{5 e \sqrt {d^2-e^2 x^2}}+\frac {77 \sqrt {d^2-e^2 x^2} (d+e x)^2}{5 e}+\frac {77 d \sqrt {d^2-e^2 x^2} (d+e x)}{2 e}+\frac {231 d^2 \sqrt {d^2-e^2 x^2}}{2 e}-\frac {231 d^3 \tan ^{-1}\left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{2 e} \]
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Rubi [A] time = 0.10, antiderivative size = 206, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 5, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.208, Rules used = {669, 671, 641, 217, 203} \[ \frac {2 (d+e x)^8}{5 e \left (d^2-e^2 x^2\right )^{5/2}}-\frac {22 (d+e x)^6}{15 e \left (d^2-e^2 x^2\right )^{3/2}}+\frac {66 (d+e x)^4}{5 e \sqrt {d^2-e^2 x^2}}+\frac {77 \sqrt {d^2-e^2 x^2} (d+e x)^2}{5 e}+\frac {77 d \sqrt {d^2-e^2 x^2} (d+e x)}{2 e}+\frac {231 d^2 \sqrt {d^2-e^2 x^2}}{2 e}-\frac {231 d^3 \tan ^{-1}\left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{2 e} \]
Antiderivative was successfully verified.
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Rule 203
Rule 217
Rule 641
Rule 669
Rule 671
Rubi steps
\begin {align*} \int \frac {(d+e x)^9}{\left (d^2-e^2 x^2\right )^{7/2}} \, dx &=\frac {2 (d+e x)^8}{5 e \left (d^2-e^2 x^2\right )^{5/2}}-\frac {11}{5} \int \frac {(d+e x)^7}{\left (d^2-e^2 x^2\right )^{5/2}} \, dx\\ &=\frac {2 (d+e x)^8}{5 e \left (d^2-e^2 x^2\right )^{5/2}}-\frac {22 (d+e x)^6}{15 e \left (d^2-e^2 x^2\right )^{3/2}}+\frac {33}{5} \int \frac {(d+e x)^5}{\left (d^2-e^2 x^2\right )^{3/2}} \, dx\\ &=\frac {2 (d+e x)^8}{5 e \left (d^2-e^2 x^2\right )^{5/2}}-\frac {22 (d+e x)^6}{15 e \left (d^2-e^2 x^2\right )^{3/2}}+\frac {66 (d+e x)^4}{5 e \sqrt {d^2-e^2 x^2}}-\frac {231}{5} \int \frac {(d+e x)^3}{\sqrt {d^2-e^2 x^2}} \, dx\\ &=\frac {2 (d+e x)^8}{5 e \left (d^2-e^2 x^2\right )^{5/2}}-\frac {22 (d+e x)^6}{15 e \left (d^2-e^2 x^2\right )^{3/2}}+\frac {66 (d+e x)^4}{5 e \sqrt {d^2-e^2 x^2}}+\frac {77 (d+e x)^2 \sqrt {d^2-e^2 x^2}}{5 e}-(77 d) \int \frac {(d+e x)^2}{\sqrt {d^2-e^2 x^2}} \, dx\\ &=\frac {2 (d+e x)^8}{5 e \left (d^2-e^2 x^2\right )^{5/2}}-\frac {22 (d+e x)^6}{15 e \left (d^2-e^2 x^2\right )^{3/2}}+\frac {66 (d+e x)^4}{5 e \sqrt {d^2-e^2 x^2}}+\frac {77 d (d+e x) \sqrt {d^2-e^2 x^2}}{2 e}+\frac {77 (d+e x)^2 \sqrt {d^2-e^2 x^2}}{5 e}-\frac {1}{2} \left (231 d^2\right ) \int \frac {d+e x}{\sqrt {d^2-e^2 x^2}} \, dx\\ &=\frac {2 (d+e x)^8}{5 e \left (d^2-e^2 x^2\right )^{5/2}}-\frac {22 (d+e x)^6}{15 e \left (d^2-e^2 x^2\right )^{3/2}}+\frac {66 (d+e x)^4}{5 e \sqrt {d^2-e^2 x^2}}+\frac {231 d^2 \sqrt {d^2-e^2 x^2}}{2 e}+\frac {77 d (d+e x) \sqrt {d^2-e^2 x^2}}{2 e}+\frac {77 (d+e x)^2 \sqrt {d^2-e^2 x^2}}{5 e}-\frac {1}{2} \left (231 d^3\right ) \int \frac {1}{\sqrt {d^2-e^2 x^2}} \, dx\\ &=\frac {2 (d+e x)^8}{5 e \left (d^2-e^2 x^2\right )^{5/2}}-\frac {22 (d+e x)^6}{15 e \left (d^2-e^2 x^2\right )^{3/2}}+\frac {66 (d+e x)^4}{5 e \sqrt {d^2-e^2 x^2}}+\frac {231 d^2 \sqrt {d^2-e^2 x^2}}{2 e}+\frac {77 d (d+e x) \sqrt {d^2-e^2 x^2}}{2 e}+\frac {77 (d+e x)^2 \sqrt {d^2-e^2 x^2}}{5 e}-\frac {1}{2} \left (231 d^3\right ) \operatorname {Subst}\left (\int \frac {1}{1+e^2 x^2} \, dx,x,\frac {x}{\sqrt {d^2-e^2 x^2}}\right )\\ &=\frac {2 (d+e x)^8}{5 e \left (d^2-e^2 x^2\right )^{5/2}}-\frac {22 (d+e x)^6}{15 e \left (d^2-e^2 x^2\right )^{3/2}}+\frac {66 (d+e x)^4}{5 e \sqrt {d^2-e^2 x^2}}+\frac {231 d^2 \sqrt {d^2-e^2 x^2}}{2 e}+\frac {77 d (d+e x) \sqrt {d^2-e^2 x^2}}{2 e}+\frac {77 (d+e x)^2 \sqrt {d^2-e^2 x^2}}{5 e}-\frac {231 d^3 \tan ^{-1}\left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{2 e}\\ \end {align*}
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Mathematica [A] time = 0.34, size = 144, normalized size = 0.70 \[ \frac {(d+e x) \left (\sqrt {1-\frac {e^2 x^2}{d^2}} \left (5446 d^5-12843 d^4 e x+8711 d^3 e^2 x^2-815 d^2 e^3 x^3-105 d e^4 x^4-10 e^5 x^5\right )-3465 d^2 (d-e x)^3 \sin ^{-1}\left (\frac {e x}{d}\right )\right )}{30 e (d-e x)^2 \sqrt {d^2-e^2 x^2} \sqrt {1-\frac {e^2 x^2}{d^2}}} \]
Antiderivative was successfully verified.
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fricas [A] time = 1.01, size = 201, normalized size = 0.98 \[ \frac {5446 \, d^{3} e^{3} x^{3} - 16338 \, d^{4} e^{2} x^{2} + 16338 \, d^{5} e x - 5446 \, d^{6} + 6930 \, {\left (d^{3} e^{3} x^{3} - 3 \, d^{4} e^{2} x^{2} + 3 \, d^{5} e x - d^{6}\right )} \arctan \left (-\frac {d - \sqrt {-e^{2} x^{2} + d^{2}}}{e x}\right ) + {\left (10 \, e^{5} x^{5} + 105 \, d e^{4} x^{4} + 815 \, d^{2} e^{3} x^{3} - 8711 \, d^{3} e^{2} x^{2} + 12843 \, d^{4} e x - 5446 \, d^{5}\right )} \sqrt {-e^{2} x^{2} + d^{2}}}{30 \, {\left (e^{4} x^{3} - 3 \, d e^{3} x^{2} + 3 \, d^{2} e^{2} x - d^{3} e\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.37, size = 129, normalized size = 0.63 \[ -\frac {231}{2} \, d^{3} \arcsin \left (\frac {x e}{d}\right ) e^{\left (-1\right )} \mathrm {sgn}\relax (d) - \frac {{\left (5446 \, d^{8} e^{\left (-1\right )} + {\left (3495 \, d^{7} - {\left (13480 \, d^{6} e + {\left (7765 \, d^{5} e^{2} - {\left (10740 \, d^{4} e^{3} + {\left (5941 \, d^{3} e^{4} - 5 \, {\left (232 \, d^{2} e^{5} + {\left (2 \, x e^{7} + 27 \, d e^{6}\right )} x\right )} x\right )} x\right )} x\right )} x\right )} x\right )} x\right )} \sqrt {-x^{2} e^{2} + d^{2}}}{30 \, {\left (x^{2} e^{2} - d^{2}\right )}^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.29, size = 309, normalized size = 1.50 \[ -\frac {e^{7} x^{8}}{3 \left (-e^{2} x^{2}+d^{2}\right )^{\frac {5}{2}}}-\frac {9 d \,e^{6} x^{7}}{2 \left (-e^{2} x^{2}+d^{2}\right )^{\frac {5}{2}}}-\frac {116 d^{2} e^{5} x^{6}}{3 \left (-e^{2} x^{2}+d^{2}\right )^{\frac {5}{2}}}+\frac {231 d^{3} e^{4} x^{5}}{10 \left (-e^{2} x^{2}+d^{2}\right )^{\frac {5}{2}}}+\frac {358 d^{4} e^{3} x^{4}}{\left (-e^{2} x^{2}+d^{2}\right )^{\frac {5}{2}}}+\frac {63 d^{5} e^{2} x^{3}}{\left (-e^{2} x^{2}+d^{2}\right )^{\frac {5}{2}}}-\frac {1348 d^{6} e \,x^{2}}{3 \left (-e^{2} x^{2}+d^{2}\right )^{\frac {5}{2}}}-\frac {152 d^{7} x}{5 \left (-e^{2} x^{2}+d^{2}\right )^{\frac {5}{2}}}-\frac {77 d^{3} e^{2} x^{3}}{2 \left (-e^{2} x^{2}+d^{2}\right )^{\frac {3}{2}}}+\frac {2723 d^{8}}{15 \left (-e^{2} x^{2}+d^{2}\right )^{\frac {5}{2}} e}+\frac {157 d^{5} x}{15 \left (-e^{2} x^{2}+d^{2}\right )^{\frac {3}{2}}}+\frac {4093 d^{3} x}{30 \sqrt {-e^{2} x^{2}+d^{2}}}-\frac {231 d^{3} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-e^{2} x^{2}+d^{2}}}\right )}{2 \sqrt {e^{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 3.17, size = 374, normalized size = 1.82 \[ -\frac {e^{7} x^{8}}{3 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}}} - \frac {9 \, d e^{6} x^{7}}{2 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}}} + \frac {77}{10} \, d^{3} e^{6} x {\left (\frac {15 \, x^{4}}{{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} e^{2}} - \frac {20 \, d^{2} x^{2}}{{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} e^{4}} + \frac {8 \, d^{4}}{{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} e^{6}}\right )} - \frac {116 \, d^{2} e^{5} x^{6}}{3 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}}} - \frac {77}{2} \, d^{3} e^{4} x {\left (\frac {3 \, x^{2}}{{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {3}{2}} e^{2}} - \frac {2 \, d^{2}}{{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {3}{2}} e^{4}}\right )} + \frac {358 \, d^{4} e^{3} x^{4}}{{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}}} + \frac {63 \, d^{5} e^{2} x^{3}}{{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}}} - \frac {1348 \, d^{6} e x^{2}}{3 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}}} - \frac {152 \, d^{7} x}{5 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}}} + \frac {2723 \, d^{8}}{15 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} e} + \frac {619 \, d^{5} x}{15 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {3}{2}}} - \frac {989 \, d^{3} x}{30 \, \sqrt {-e^{2} x^{2} + d^{2}}} - \frac {231 \, d^{3} \arcsin \left (\frac {e x}{d}\right )}{2 \, e} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (d+e\,x\right )}^9}{{\left (d^2-e^2\,x^2\right )}^{7/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (d + e x\right )^{9}}{\left (- \left (- d + e x\right ) \left (d + e x\right )\right )^{\frac {7}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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